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1. RussellsParadox July 3rd, 2010 9:34 am :

   @bigzacaq actually the ODDS are 649739 to 1.

2. sienipata July 3rd, 2010 9:34 am :

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3. DarkCloudedSoul July 3rd, 2010 9:34 am :

   Pardon my ignorance, as I am new to the sport of poker, but how does knowing this actually help you? Is it supposed to help you decide when to fold or bet to the river?

4. MrLoouie86 July 3rd, 2010 9:34 am :

   dont worry i got it lol

5. MrLoouie86 July 3rd, 2010 9:34 am :

   why u multiply there by 3/51?

6. bigzacaq July 3rd, 2010 9:34 am :

   1 in 649740 hands

7. USERNAMEKLEMPTOR July 3rd, 2010 9:34 am :

   what are the odds od ROYAL FLUSH?

8. hyppEreL July 3rd, 2010 9:34 am :

   they say the chance of getting any pocket pair , not two 9`s.

9. lostcause31 July 3rd, 2010 9:34 am :

   Because a physicist clearly trumps any other field that would utilize math.

10. vaico July 3rd, 2010 9:34 am :

    La probabilidad de sacar CUALQUIER PAR es la misma, no porque en la carta diga “A” en vez de “9″ va a cambiar la probabilidad…

11. notengonickcojones July 3rd, 2010 9:34 am :

    what are u talking about? stupid, i’m physicist don’t try to teach me anything.

12. chadkwong July 3rd, 2010 9:34 am :

    ANY pocket pair is 5.8..

13. notengonickcojones July 3rd, 2010 9:34 am :

    the chance of getting two 9 is: 4/52 * 3/51 wich is approx: 0,5%.
    the chance of getting two pairs, no matter what pair, is: 3/51 wich is approx: 5.9% or 1 every 16 hands. don’t trust these videos if u want money, look for a course in mathematics.

14. jmb765 July 3rd, 2010 9:34 am :

    Yeah, I see you’re right. It was just a quick reply at the time, I don’t guess I actually stopped to think about it. Thanks man.

15. SuperChuck3 July 3rd, 2010 9:34 am :

    chance, can’t* sorry for the spelling

16. SuperChuck3 July 3rd, 2010 9:34 am :

    The change of getting two 9′s is 1/221, lol, same as Aces. You can just double it to get your fraction right. The change of getting any pocket pair is 100% of getting any card (example a Jack), and then there’s 3 Jacks left for the 2nd card, and 51 cards left in the deck. 3/51 = 1/17 change of any Pocket pair.

17. SuperChuck3 July 3rd, 2010 9:34 am :

    1/17 chance of getting pockets, 13 different pocket hands 17*13=221, 1/221 of getting 1 certain pocket pair (example A’s). But she said 1/222, so they obvioiusly rounded at once point when they put it to decimals, no biggie.

18. jmb765 July 3rd, 2010 9:34 am :

    Well, she referred to pocket pairs first, which has a fairly good percentile, but when she went on to the pocket aces, she said something like 1/222 hands you’ll get it. She referred to it because it is the best possible pocket pair you can have, and because there are only 4 of those cards in the deck, the chances of you getting those SPECIFIC cards are that ratio. The first time she mentioned it, she was talking about pocket pairs in general.

19. djax4mvp July 3rd, 2010 9:34 am :

    no it wouldn’t, if nobody had what u were looking for than ur odds would increase. the odds stay the same.

20. djax4mvp July 3rd, 2010 9:34 am :

    yeah but their is only 3 nines if u already have one.

21. saintsrulethegay July 3rd, 2010 9:34 am :

    no it meant any pocket pair, not necaserily a pair of 9′s but they just used that as an example for a pocket pair

22. ganky6 July 3rd, 2010 9:34 am :

    OK… i get it. You are right

23. ferraztube July 3rd, 2010 9:34 am :

    The odds aren’t different.
    The first example was about getting any pair doesn’t matter which. The Aces example is about getting one particular pair so: 5,8% for any pair divided by 13 cards. 5.8/13 = 0.45

24. ganky6 July 3rd, 2010 9:34 am :

    I dont get it either.
    Why is the chance higher to get two 9′s than two Aces?
    There are 4 Aces in a 52 deck and 4 9′s in a 52 deck… so why are the odds different???

25. jurgen1980 July 3rd, 2010 9:34 am :

    to hit a pair of course, not a set.

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